# Algebra Equation Solver

Algebra equation solvers make learning algebra easy. A lot of online sites and resources exist to make algebra simple. With step-by-step explanations and a lot of solved and unsolved practice problems, they provide students with plenty of opportunities to hone their algebra solving skills. As any student knows, practice is the key to scoring perfect grades for algebra. This is where an Algebra equation solver makes things easy. An algebra equation solver can be an online tutor who works with a student to make the subject easy. Online tutors are available round-the-clock for a one-on-one personalized session any time a student needs help. Algebra equation solver online is convenient and quick. Students find it especially helpful because these solvers are available 24x7 letting you learn whenever they feel like.

## Equation Solver Online

Algebra equation solvers are an ideal way to learn math conveniently and simply. Make the most of the online resources and find an excellent algebra equation solver. A quick internet search will lead you to numerous algebra equation solvers. Besides personalized help these sites also offer a huge database of practice problems for algebra. The sites cover all kinds of problems from simple to complex and also include tricky algebra word problems. These online algebra equation solvers will work with you on making the process of solving all these problems easy. Most of these websites have separate sections which also explain the theory part which you can refer to if you ever get stuck at a question.

## Solved Examples

Question 1: Factor 6x2 - 7x + 2
Solution:
Given quadratic equation
6x2 - 7x + 2

6x2 - 7x + 2 = 6x2 - 3x - 4x + 2

= 3x(2x - 1) - 2(2x - 1)

= (3x - 2)(2x - 1)

=> 6x2 - 7x + 2 = (3x - 2)(2x - 1)

Question 2: Find the sum of four consecutive integers such that the sum of first, second and third integer is equal to two times the fourth integer.

Solution:
First integer = x

Second integer = x + 1

Third integer = x + 2

Forth integer = x + 3

The statement states:

Sum of first, second and third integer is equal to two times the fourth integer

=> x + (x + 1) + (x + 2) = 2(x + 3)

=> 3x + 3 = 2x + 6

=> 3x - 2x = 6 - 3

=> x = 3

First integer = 3

Second integer = 3 + 1 = 4

Third integer = 3 + 2 = 5

Forth integer = 3 + 3 = 6

=> Sum of four consecutive integers is 18 (ie 3 + 4 + 5 + 6 = 18).

Question 3: If Riffela travel 30 miles in two hours, how far he travel in four hours.

Solution:
Given, Riffela travel 30 miles in two hours

Let he traveled 'd' miles in 4 hours.

=> $\frac{30}{2} = \frac{d}{4}$

=> 15 = $\frac{d}{4}$

=> 15 * 4 = d

=> 60 = d

=> Hence, Riffela traveled 60 miles in 4 hours.

Question 4: Solve for p, p + (p + 4) + 6(p - 4) + 3 = 68

Solution:
Given, p + (p + 4) + 6(p - 4) + 3 = 68

=> p + (p + 4) + 6(p - 4) + 3 = 68

=> p + p + 4 + 6p - 24 + 3 = 68

=> 8p - 17 = 68

Add 17 both sides

=> 8p - 17 + 17 = 68 + 17

=> 8p = 85

Divide each side by 8

=> p = $\frac{85}{8}$